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关于连续统假设2~(ω~(0))=ω_1的证伪凡数皆可数2~(ω~(0))=ω_1的证明
引用本文:陈自立.关于连续统假设2~(ω~(0))=ω_1的证伪凡数皆可数2~(ω~(0))=ω_1的证明[J].淮阴师范学院学报(自然科学版),2014(1):23-39.
作者姓名:陈自立
作者单位:海宁市建设局浙江华恒建筑设计有限公司,浙江海宁314400
摘    要:通过破连续统假设的基石即其中的基本定理与基本方法,得到主要结果:证伪"定理:ω1是基数";康托定理的证伪;对角线法不可取;从正面几个角度几种方法来证明连续统0,1]是可数的.得出关于连续统的一个新证明:2ω0=ω0.用进制法证明2ω0可数;用一一对应法证明0,1]实数区间的可数性.

关 键 词:连续统[0  1]  可数的基数χ0  不可数的基数χ1  一一对应  数的进制  对角线法

The Falsity of Continuum Hypothesis2ω0 =ω1 The Mathematical Justification for All Numbers are Countable 2ω0 =ω0
CHEN Zi-li.The Falsity of Continuum Hypothesis2ω0 =ω1 The Mathematical Justification for All Numbers are Countable 2ω0 =ω0[J].Journal of Huaiyin Teachers College(Natrual Science Edition),2014(1):23-39.
Authors:CHEN Zi-li
Institution:CHEN Zi-li (Haining Construction Bureau & Zhejiang Huaheng ArchitecturalDesign CO. LTD, Haining Zhejinag 314400, China)
Abstract:By the falsity of “Theorem:ω1 is a cardinal”and the falsity of Cantor Theorem or Improper use of the diagonal method obtani the main results are the following:2ω0 equal toω1 (2ω0 =ω1 ) Cantor thought it was true, which means 0, 1] is uncountable.We call it Continuum Hypothesis .This article first rocks the cor-nerstone of Continuum Hypothesis , that is to say , the basic principle and method adopted in this hypothesis . Then to clarify the problem, several methods are used to prove that the continuum 0,1] is countable.A new mathematical proof of continuum:2ω0 =ω0;To prove 2ω0 is countable by using decimal method;To prove the countability of the set of real numbers 0,1] by using the rule of one-one correspondence.
Keywords:continuum  countable cardinal X1  uncountable cardinal X1  one-one correspondence  diagonal method
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