| 自然数等于它的各位数同次幂之和的解 |
| |
| 引用本文： | 杨作立. 自然数等于它的各位数同次幂之和的解[J]. 汕头大学学报(自然科学版), 1992, 7(1): 47-55 |
| |
| 作者姓名： | 杨作立 |
| |
| 摘 要： | 本文首先证明,对于任一个大于0的整数m,自然数要等于它的各位m次幂之和,自然数的位数p与幂次m必须满足不等式: 1+[mlg2]≤p≤1+[mlg9+1g(m-1)] 才有可能,然后,在这基础上,再求出m=1,2,……,11的解,最后附FORTRAN77源程序一份,供上机计算时参考.
|
| 关 键 词： | 自然数 位 幂 |
A Way for Finding out a Natural Number Which Equals the Sum of Each of the Digits to the Same Power |
| |
| Yang Zuoli. A Way for Finding out a Natural Number Which Equals the Sum of Each of the Digits to the Same Power[J]. Journal of Shantou University(Natural Science Edition), 1992, 7(1): 47-55 |
| |
| Authors: | Yang Zuoli |
| |
| Abstract: | this paper first proves the following inequality: Where p is the number of digits of a natural number; m is the power of each digit. Then, solutions to this problem are provided for cases where m=1, 2, 3, ……, 11 Finally, a source program in FORTRAN—77 for finding out these natural numbers is given. |
| |
| Keywords: | natural number digit power |
| 本文献已被 CNKI 维普 等数据库收录！ |
|
