中国邮路问题的0-1规划解法

在用“奇偶点图上作业法”求解“中国邮路问题”时,需检查图中的每一个回路.当图中回路较多时,检查不便且易出错.针对此,本文建立了求解“中国邮路问题”的0-1规划模型,并给出了算例。     

船舶二维图形交换研究

船舶图形在不同的CAD系统中交换，共享是现代船舶工业发展的需求，主要论述了如何在2个船用CAD软件（CADDS5和TRIBON M1）之间进行二维图形信息的交换。     

Molecular cloning and expression of interleukin Ibeta (IL-1β) from red seabream (Pagrus major)

The interleukin 1β (IL-1β) cDNA was cloned from the red seabream (Pagrus major) by homology cloning strategy. A cDNA fragment was amplified by PCR using two degenerated primers, which were designed according to the conserved regions of other known IL-1β sequences, and elongated by 3' ends and 5' ends RACE PCR to get the full length coding sequence of red seabream IL-1β (RS IL-1β). The sequence contained 1252 nucleotides that included a 5' untranslated region (UTR) of 84bp, a 3' UTR of 410 bp and an open reading frame (ORF) of 759 nucleotides which could be translated into a putative peptide of 253 amino acids with molecular weight of 28.6 kD and putative isoelectric point pI of 5.29. The deduced peptide contained two potential N-glycosylation sites and an identifiable IL1 family signature, but lacked the signal peptide and the clear ICE cut site, which were common in other nonmammalian IL-1β genes. The RS IL-1β had the highest homology with piscine IL-1β according to phylogenetic tree analysis.     

实现细粒煤深度脱硫产业化的研究

根据我国高硫煤的赋存特点,提出采用微细介质重介旋流器及细泥选择性絮凝组合工艺实现细粒煤的深度脱硫,无机硫脱除率可大幅度提高,分选下限明显降低,是实现煤炭深度脱硫降灰产业化的有效技术途径.     

玉米两个自交系及其杂交F_1染色体G-带带型的比较

对玉米两个自交系京7和华5及其杂交F_1的染色体G-带带型进行了比较研究。结果表明,两自交系的G-带中A型带之间的相似点很多,有的完全一致;而B型带在带的数目和分布位置上有差异。杂交F_1的G-带带型具有杂合性,B型带的杂合性尤为明显。文中讨论了G-带、C-带和N-带并存等问题。     

电镀添加剂的NMR定量分析

本文叙述了用于定量分析电镀添加剂中丙烯磺酸钠和糖精钠的快速、准确、精密的ＮＭＲ分析方法．该方法是依据每个组分的ＮＭＲ特征信号和用作内标的四甲基澳化按ＮＭＲ信号的积分比值建立的，各组分不需要预先分离．     

苏云金杆菌库斯塔变种(HD-1)对菜青虫杀虫效果的研究

通过实验室饲料感染方法和大田喷杀对比试验研究，表明发酵培养基中添加花生饼可以提高HD—1的杀虫效果，且添加浓度与HD—1菌株毒力呈正相关，用添加了花生饼的固体浅盘发酵培养液比市售工业化生产的同类杀虫剂杀虫效果要高得多。     

硬盘分区链表中结点信息的完全恢复算法

通过对分区链表中结点信息的研究 ,及前后结点中相关数据项比较之后 ,参照磁盘基数表中所记录的相应分区长度 ,给出了其中任一结点或整个分区链表丢失之后的修复算法     

Ces_p(E_1,E_2)的k一致凸性

文章讨论了Banach空间的k一致凸性在Ces_p(E_1,E_2)中的提升问题.