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81.
湿地松对松针褐斑病的抗性测定 总被引:2,自引:0,他引:2
从松针褐斑病(Lecanosticta acicola)重病林分中选出36个湿地松(Pinus elliottii)抗病表现型优树无性系,用人工喷洒病菌孢子液接种法对其进行抗病测定,结果表明,有22个是高度抗病的。与用松针褐斑病产生的毒素粗提液处理上述无性系的离体针叶进行抗病性测定的结果基本一致,相关系数为0.80。 相似文献
82.
介绍一种用单片机控制的结构简单、成本低的正(余)弦函数发生器,论述了其基本原理,给出了硬件框图和软件框图,可用于计算机控制的调速系统中。 相似文献
83.
84.
LIUYan HUYi-jun 《武汉大学学报:自然科学英文版》2004,9(4):399-403
We consider a risk model with a premium rate which varies with the level of free reserves. In this model, the occurrence of claims is described by a Cox process with Markov intensity process, and the influence of stochastic factors is considered by adding a diffusion process. The integro-differential equation for the ruin probability is derived by a infinitesimal method. 相似文献
85.
在分析了教育技术专业现在面临的许多外界环境变化的同时 ,从市场、商品经济学的有关角度 ,提出了关于教育技术专业本科课程设置的几点想法 ,并在实践的基础上给出了一些具体的做法 相似文献
86.
87.
J. Bruce Brackenridge 《Archive for History of Exact Sciences》2003,57(4):313-336
In the 1687 Principia, Newton gave a solution to the direct problem (given the orbit and center of force, find the central force) for a conic-section
with a focal center of force (answer: a reciprocal square force) and for a spiral orbit with a polar center of force (answer:
a reciprocal cube force). He did not, however, give solutions for the two corresponding inverse problems (given the force
and center of force, find the orbit). He gave a cryptic solution to the inverse problem of a reciprocal cube force, but offered no solution for the reciprocal square force. Some take this omission as an indication that Newton could not solve the reciprocal square, for, they ask, why else
would he not select this important problem? Others claim that ``it is child's play' for him, as evidenced by his 1671 catalogue
of quadratures (tables of integrals). The answer to that question is obscured for all who attempt to work through Newton's
published solution of the reciprocal cube force because it is done in the synthetic geometric style of the 1687 Principia rather than in the analytic algebraic style that Newton employed until 1671. In response to a request from David Gregory
in 1694, however, Newton produced an analytic version of the body of the proof, but one which still had a geometric conclusion.
Newton's charge is to find both ``the orbit' and ``the time in orbit.' In the determination of the dependence of the time on orbital position, t(r), Newton
evaluated an integral of the form ∫dx/x
n
to calculate a finite algebraic equation for the area swept out as a function of the radius, but he did not write out the
analytic expression for time t = t(r), even though he knew that the time t is proportional to that area. In the determination
of the orbit, θ (r), Newton obtained an integral of the form ∫dx/√(1−x2) for the area that is proportional to the angle θ, an integral he had shown in his 1669 On Analysis by Infinite Equations to be equal to the arcsin(x). Since the solution must therefore contain a transcendental function, he knew that a finite
algebraic solution for θ=θ(r) did not exist for ``the orbit' as it had for ``the time in orbit.' In contrast to these two
solutions for the inverse cube force, however, it is not possible in the inverse square solution to generate a finite algebraic
expression for either ``the orbit' or ``the time in orbit.' In fact, in Lemma 28, Newton offers a demonstration that the
area of an ellipse cannot be given by a finite equation. I claim that the limitation of Lemma 28 forces Newton to reject the
inverse square force as an example and to choose instead the reciprocal cube force as his example in Proposition 41.
(Received August 14, 2002)
Published online March 26, 2003
Communicated by G. Smith 相似文献
88.
本文以教学研究为基础,系统研究不对称D—A反应区域选译性规律,并运用前线分子轨道理论,采用图解量子化学方法予以理论解析。 相似文献
89.
90.