全文获取类型
收费全文 | 15403篇 |
免费 | 1029篇 |
国内免费 | 555篇 |
专业分类
系统科学 | 1572篇 |
丛书文集 | 259篇 |
教育与普及 | 246篇 |
理论与方法论 | 313篇 |
现状及发展 | 900篇 |
研究方法 | 32篇 |
综合类 | 13663篇 |
自然研究 | 2篇 |
出版年
2024年 | 39篇 |
2023年 | 99篇 |
2022年 | 165篇 |
2021年 | 190篇 |
2020年 | 139篇 |
2019年 | 55篇 |
2018年 | 788篇 |
2017年 | 830篇 |
2016年 | 536篇 |
2015年 | 273篇 |
2014年 | 324篇 |
2013年 | 362篇 |
2012年 | 622篇 |
2011年 | 1322篇 |
2010年 | 1182篇 |
2009年 | 834篇 |
2008年 | 966篇 |
2007年 | 1201篇 |
2006年 | 469篇 |
2005年 | 492篇 |
2004年 | 456篇 |
2003年 | 500篇 |
2002年 | 450篇 |
2001年 | 404篇 |
2000年 | 377篇 |
1999年 | 508篇 |
1998年 | 445篇 |
1997年 | 473篇 |
1996年 | 393篇 |
1995年 | 308篇 |
1994年 | 293篇 |
1993年 | 283篇 |
1992年 | 271篇 |
1991年 | 206篇 |
1990年 | 203篇 |
1989年 | 171篇 |
1988年 | 158篇 |
1987年 | 103篇 |
1986年 | 52篇 |
1985年 | 23篇 |
1984年 | 7篇 |
1983年 | 9篇 |
1982年 | 2篇 |
1981年 | 3篇 |
1967年 | 1篇 |
排序方式: 共有10000条查询结果,搜索用时 15 毫秒
61.
根据塑料挤出的特点,在编程实现对型材截面轮廓凸凹性自动判断的基础上,采用射线法与比例间隔法相结合的方法,确定流道入口圆周上型值点的位置.以三次多项式作为流道模腔型曲线的数学模型,依据流线型要求给出的初始、边界条件,得出型曲线的数学方程.构建了挤出模流道的三维参数化曲面模型.有限元分析结果显示,该方法创建的流线型流道模型,其流动稳定性和平顺性都优于直线型流道. 相似文献
62.
刘证 《鞍山科技大学学报》2002,25(6):456-459
考虑了形如∫xap(t)f(t)dt∫xap(t)g(t)dt 和 ∑ki=1piai∑ki=1pibi的两种商在一定条件下所具有的单调性质,推广了某些熟知的结果. 相似文献
63.
排球运动中的供能特点与营养补充 总被引:3,自引:0,他引:3
物质和能量代谢是人体各组织器官机能活动的基础,应用运动时物质和能量代谢规律指导训练期间的营养安排是非常有益的.通过对排球运动的特点进行分析,结合各供能系统的特点以及各种能量物质分解的先后关系,简要陈述排球比赛中的物质和能量代谢,分析了排球运动中疲劳产生的可能原因,有针对性地提出训练中的营养安排以及应当注意补充的几种营养物质。 相似文献
64.
本文介绍了阶段原型法(SPA)及其支持环境(PEMIS)的总体结构和主要功能,探讨了知识库和推理机制在循环控制中的作用,以及软件重用技术、图形接口技术和应用生成技术等实现技术。 相似文献
65.
对经过分级的六种均齐粉粒状物料进行透气性系数测定。结果表明:球形小米颗粒((?)_p=1.70mm),透气性系数K=1.191×10~(-9)m~2,在整个固定床范围内都符合达西定律;石灰石粉((?)_P=0.900mm),K=5.831×10~(-10)m~2。文中还讨论了达西定律的适用依据和透气性系数的影响因素。 相似文献
66.
67.
LIUYan HUYi-jun 《武汉大学学报:自然科学英文版》2004,9(4):399-403
We consider a risk model with a premium rate which varies with the level of free reserves. In this model, the occurrence of claims is described by a Cox process with Markov intensity process, and the influence of stochastic factors is considered by adding a diffusion process. The integro-differential equation for the ruin probability is derived by a infinitesimal method. 相似文献
68.
蓬勃发展的中国合成革工业 总被引:6,自引:0,他引:6
阐述了我国人造革,合成革行业发展现状及发展特点,提出了中国人造革,合成革行业的工作重点及发展方向。 相似文献
69.
J. Bruce Brackenridge 《Archive for History of Exact Sciences》2003,57(4):313-336
In the 1687 Principia, Newton gave a solution to the direct problem (given the orbit and center of force, find the central force) for a conic-section
with a focal center of force (answer: a reciprocal square force) and for a spiral orbit with a polar center of force (answer:
a reciprocal cube force). He did not, however, give solutions for the two corresponding inverse problems (given the force
and center of force, find the orbit). He gave a cryptic solution to the inverse problem of a reciprocal cube force, but offered no solution for the reciprocal square force. Some take this omission as an indication that Newton could not solve the reciprocal square, for, they ask, why else
would he not select this important problem? Others claim that ``it is child's play' for him, as evidenced by his 1671 catalogue
of quadratures (tables of integrals). The answer to that question is obscured for all who attempt to work through Newton's
published solution of the reciprocal cube force because it is done in the synthetic geometric style of the 1687 Principia rather than in the analytic algebraic style that Newton employed until 1671. In response to a request from David Gregory
in 1694, however, Newton produced an analytic version of the body of the proof, but one which still had a geometric conclusion.
Newton's charge is to find both ``the orbit' and ``the time in orbit.' In the determination of the dependence of the time on orbital position, t(r), Newton
evaluated an integral of the form ∫dx/x
n
to calculate a finite algebraic equation for the area swept out as a function of the radius, but he did not write out the
analytic expression for time t = t(r), even though he knew that the time t is proportional to that area. In the determination
of the orbit, θ (r), Newton obtained an integral of the form ∫dx/√(1−x2) for the area that is proportional to the angle θ, an integral he had shown in his 1669 On Analysis by Infinite Equations to be equal to the arcsin(x). Since the solution must therefore contain a transcendental function, he knew that a finite
algebraic solution for θ=θ(r) did not exist for ``the orbit' as it had for ``the time in orbit.' In contrast to these two
solutions for the inverse cube force, however, it is not possible in the inverse square solution to generate a finite algebraic
expression for either ``the orbit' or ``the time in orbit.' In fact, in Lemma 28, Newton offers a demonstration that the
area of an ellipse cannot be given by a finite equation. I claim that the limitation of Lemma 28 forces Newton to reject the
inverse square force as an example and to choose instead the reciprocal cube force as his example in Proposition 41.
(Received August 14, 2002)
Published online March 26, 2003
Communicated by G. Smith 相似文献
70.