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关于对角占优矩阵A的n阶Hadamard积的不等式的证明
引用本文:翁东东.关于对角占优矩阵A的n阶Hadamard积的不等式的证明[J].大理学院学报,2006,5(8):11-12,22.
作者姓名:翁东东
作者单位:泉州师范学院,福建,泉州,362000
摘    要:将双严格对角占优矩阵的性质与Hadamard不等式相结合,得出一个具有双严格对角占优性质的矩阵的Hadamard不等式,将以上内容扩展至A自身Hadamard乘积,得到一个关于AOA的不等式,再将其进一步扩展得到一个双严格对角占优矩阵A的n阶Hadamard积的不等式。

关 键 词:Hadamard不等式  对角占优矩阵  对称正定矩阵
文章编号:1672-2345(2006)08-0010-02
收稿时间:05 12 2006 12:00AM
修稿时间:2006-05-12

On Double Strictly Diagonal Asset Matrix Hadamard Inequality
WENG Dong-dong.On Double Strictly Diagonal Asset Matrix Hadamard Inequality[J].Journal of Dali University,2006,5(8):11-12,22.
Authors:WENG Dong-dong
Institution:Quanzhou Nomal University, Quanzhou, Fujian 362000,China
Abstract:This article take the Hadamard inequality theorem as the main principle, Occupies the superior matrix and Asia using the double strict opposite angle is deciding the matrix the relation, occupies the double strict opposite angle the superior matrix the nature and the Hadamard inequality unifies. Obtains to have the double strict opposite angle to occupy the dominance archery target matrix the Hadamard inequality, Again above the content will expand to A own Hadamard product, obtains about the AoA inequality, again further expands it obtains a double strict opposite angle to occupy the inequality which superior matrix A n step Hadamard accumulates, Finally uses proves the result to obtain the double strict opposite angle again to occupy superior matrix A, B Hadamard accumulates AoB the inequality.
Keywords:Hadamard inequality of positive definite  Asia Auxiliary matrix  opposite angles-dominant matrix
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