| SO3光解反应的热力学机制 |
| |
| 引用本文： | 高志崇.SO3光解反应的热力学机制[J].泰山学院学报,2009,31(3):55-58. |
| |
| 作者姓名： | 高志崇 |
| |
| 作者单位： | 泰山学院,化学与环境科学系,山东,泰安,271021 |
| |
| 摘 要： | SO3光解反应的反应式为2SO3＋hν（λ1）2SO2＋O2＋hν（λ2）,因而SO3的转化率α与温度T,波长λ1和λ2有关.利用公式△rG0m＋RTInK0p=0.1196λ1-0.1196λ2计算了当T=318K,λ1=211nm,α=35%时,λ2=277.8nm,这一波长正好位于SO2的吸收峰,从而解释了为什么在318K时SO3的转化率为35%.
|
| 关 键 词： | 光化反应 吉布斯自由能 转化率 平衡常数 |
Percent Conversions and Equilibrium Constants of SO3 Photolytic Reaction |
| |
| GAO Zhi-chong.Percent Conversions and Equilibrium Constants of SO3 Photolytic Reaction[J].Journal of Taishan University,2009,31(3):55-58. |
| |
| Authors: | GAO Zhi-chong |
| |
| Institution: | GAO Zhi - chong (Department of Chemistry and Environmental Science,Taishan University, Tai＇an,271021, China) |
| |
| Abstract: | The formula of SO3 photolytic reaction is 2SO3＋hν（λ1）2SO2＋O2＋hν（λ2）, so SO3 per-cent conversion （α） is related with temperature and two light wavelengths （λ1 ,λ2 ）. If T = 318K, λ1 =211nm and α =35% ,λ2is calculated by the formula△rG0m＋RTInK0p=0.1196λ1-0.1196λ2,it is 277.8 nm,just in the range of SO2 absorption peak. The result explains why SO3 conversion efficiency （α） is 35%. |
| |
| Keywords: | photochemical reaction Gibbs energy percent conversion equilibrium constant |
| 本文献已被 维普 万方数据 等数据库收录！ |
|
