PET-云母复合体系的双重Tg转变

本文用粘弹谱仪、x射线衍射、DSC研究了PET—云母复合物的Tg区域的多重转变等松驰转变行为,探讨了加工、云母填充对PET—云母材料性能影响的分子运动机理。不同热历史(如不同成型条件、热处理等)使聚合物分子形成不同链段运动;处于高温位的Tg(u)其运动单元是受结晶、内应力、填料作用影响的非晶区链段。     

高低杠“屈体腾越转体180°再握”动作的运动学分析

本文采用固定高速摄影及影片数字化研究方法，对山西体操运动员郭佳在１９９０年新创的屈体腾越转体１８０°再握动作进行运动学分析，得出各技术环节的运动学数据，找到其动作的运动学特征，为我国体操教练员和运动员提供参考。     

酵母菌耐性与海藻糖积累的初步研究

对 11株酵母菌进行了渗透压、乙酸、冷冻、乙醇耐性实验及海藻糖积累的比较。实验表明 ,渗透压耐性和乙酸耐性较好的菌株 ,其积累海藻糖的能力较强 ;而抗冷冻和乙醇耐性与海藻糖的积累能力无明显的相关性。     

曲棍球赛场技战术的计算机分析系统

介绍在ＩＢＭ－ＰＣ／ＸＴ计算机上实现的曲棍球赛场统计系统的研制过程、设计思想、采用的方法、软件设计与功能、技术指标操作步骤以及使用效果。     

档案行政执法要采取监督与业务指导相结合

依法治档，很大程度是通过档案行政执法来实现的。档案行政执法是档案法制建设不可缺少的重要环节。也是依法治档的关键因素和重大举措。要使档案法律、法规落到实处。关键在于从严监督。文章探讨了如何把监督和业务指导有机结合起来，更好地为档案事业服务。     

发展型方程的快速Legendre谱τ逼近

摘要：以发展型模型方程为背景，建立了半离散和全离散的Legendre谱τ格式，并用反向递推法和奇偶分解法建立了Legendre谱τ方法的快速算法，在每一时间层上，其运算量仅为O(N)．运用离散能量法严格证明了全离散格式在时空方向的收敛阶分别为τ^2和N^1-m．数值结果显示了算法的有效性．     

Ruin Probability with Variable Premium Rate and Disturbed by Diffusion in a Markovian Environment

We consider a risk model with a premium rate which varies with the level of free reserves. In this model, the occurrence of claims is described by a Cox process with Markov intensity process, and the influence of stochastic factors is considered by adding a diffusion process. The integro-differential equation for the ruin probability is derived by a infinitesimal method.     

SolidWorks 2001 Plus三维CAD软件在锅炉设计中的应用

对手工制图、二维CAD制图和三维CAD制图3种方式进行了比较，指出三维CAD软件有取代二维CAD软件的趋势。成功应用SolidWorks 2001Plus三维CAD软件进行锅炉设计，可极大提高企业的产品开发效率。     

砂质泥岩工程地质特性及其灾害防治对策

文章阐述了砂质泥岩的工程地质特性及其风化规律，在不同状态下形成的灾害，提出了防治对策。     

Newton's Easy Quadratures ``Omitted for the Sake of Brevity'

In the 1687 Principia, Newton gave a solution to the direct problem (given the orbit and center of force, find the central force) for a conic-section with a focal center of force (answer: a reciprocal square force) and for a spiral orbit with a polar center of force (answer: a reciprocal cube force). He did not, however, give solutions for the two corresponding inverse problems (given the force and center of force, find the orbit). He gave a cryptic solution to the inverse problem of a reciprocal cube force, but offered no solution for the reciprocal square force. Some take this omission as an indication that Newton could not solve the reciprocal square, for, they ask, why else would he not select this important problem? Others claim that ``it is child's play' for him, as evidenced by his 1671 catalogue of quadratures (tables of integrals). The answer to that question is obscured for all who attempt to work through Newton's published solution of the reciprocal cube force because it is done in the synthetic geometric style of the 1687 Principia rather than in the analytic algebraic style that Newton employed until 1671. In response to a request from David Gregory in 1694, however, Newton produced an analytic version of the body of the proof, but one which still had a geometric conclusion. Newton's charge is to find both ``the orbit' and ``the time in orbit.' In the determination of the dependence of the time on orbital position, t(r), Newton evaluated an integral of the form ∫dx/x <sup>n</sup> to calculate a finite algebraic equation for the area swept out as a function of the radius, but he did not write out the analytic expression for time t = t(r), even though he knew that the time t is proportional to that area. In the determination of the orbit, θ (r), Newton obtained an integral of the form ∫dx/√(1−x<sup>2</sup>) for the area that is proportional to the angle θ, an integral he had shown in his 1669 On Analysis by Infinite Equations to be equal to the arcsin(x). Since the solution must therefore contain a transcendental function, he knew that a finite algebraic solution for θ=θ(r) did not exist for ``the orbit' as it had for ``the time in orbit.' In contrast to these two solutions for the inverse cube force, however, it is not possible in the inverse square solution to generate a finite algebraic expression for either ``the orbit' or ``the time in orbit.' In fact, in Lemma 28, Newton offers a demonstration that the area of an ellipse cannot be given by a finite equation. I claim that the limitation of Lemma 28 forces Newton to reject the inverse square force as an example and to choose instead the reciprocal cube force as his example in Proposition 41. (Received August 14, 2002) Published online March 26, 2003 Communicated by G. Smith