关于Diophantine方程(xm-1)(xn-1)=y2

设N是全体正整数的集合.证明了方程(xm-1)(xn-1)=y2,x,y,m,n∈N,x＞1,n＞m≥1的全部整数解为(x,y,m,n)=(7,120,1,4),(3,22,1,5),(3,44,2,5),(2,21,3,6)(k2-1,k3-2k,1,2),其中k∈Z,k＞1.     

关于Diophantine方程(axm+1)/(ax+1)=yn

设a，m，n是适合min(m，n)＞2的正整数。本文证明了：当m=1(mod n)时，方程(ax^m 1)／(ax 1)=y^n无正整数解(x，y)适合min(x，y)＞1。     

关于Diophantine方程（ax^m-1）/（ax-1）=y^n＋1

设a,m是适合m＞2的正整数.证明了当a＞1时,方程仅有有限多组正整数解(x,y,n)适合min(x,y,n)＞1,而且这些解都满足yn＜2xm-1≤2am2-3m+2.     

Diophantine方程2~m+1=3y~n

证明了方程 2 m+1=3yn 没有适合m >2 ,n >1,y >1的正整数解 (y ,m ,n)     

关于Diophantine方程(axm+1)/(ax+1)=yn+1

设a,m是大于1的正整数.该文证明了：当m＞2时,方程（ax^m＋1）/（ax＋1）=y^n＋1仅有有限多组正整数解（x,y,n）适合min（x,y,n）＞1,而且这些解都满足y6n＜x^m-1≤a^m2-3m＋2.     

关于Diophantine方程(axm-1)/(ax-1)=yn

设a,m,n是适合min(m,n)＞2的正整数.证明了当m≡1(mod n)时,方程(axm-1)/(ax-1)=yn无正整数解(x,y)适合min(x,y)＞1.     

方程(axm+1)/(ax+1)=yn的正整数解

设a,m是大于1的正整数,证明:当m>2,方程(axm 1)/(ax 1)=yn仅有有限多组解(x,y,n)适合min(x,y,n)>1,而且这些解都满足yn相似文献   

丢番图方程y(y+1)(y+2)(y+3)=n~2 x(x+1)(x+2)(x+3)解的研究

设n1是正整数,利用Pell方程的正整数解的一组恒等式和高次丢番图方程的结果,研究了丢番图方程y(y+1)(y+2)(y+3)=n~2x(x+1)(x+2)(x+3)的正整数解(x,y),分别在2|/n,3|x的情形下和n不同素因数的个数不超过2的情形下,证明了该方程没有正整数解(x,y).     

关于Diophantine方程x3+1=Dyn

设D是不能被形如6k+1的素数整除的正整数,文章证明了:方程X3+1=Dyn仅当D=20时 有正整数解(x,y,n)=(19,7,3)适合x>1以及n>2。     

关于Diophantine方程xp-1-1=2mpyn

设p是奇素数，n是大于1的奇数，证明了：当p≡7(mod12)时，方程x^p-1-1=2^mpy^n无正整数解(x，y，m，n)。     

关于指数Diophantine方程(a~n-1)(b~n-1)=x~2

设a,b是不同的正整数.运用初等数论方法证明了:当a≡0(mod 2)且b≡3(mod 8)时,方程(an-1)(bn-1)=x2没有适合n>1的正整数解(x,n).     

Liquid-Liquid Equilibrium for 1-Butanol-Water-KF and 1-Butanol-Water-K2CO3 Systems

KF or K2CO3 was added into the 1-butanol-water system and two phases were formed： water-rich phase （water phase） and 1-butanol-rich phase （1-butanol phase）. The liquid liquid equilibrium （LLE） data for 1-butanol-water-KF and 1-butanol-water-K2CO3 systems were measured at 25℃ and showed that 1-butanol phase contained negligible salt and water phase contained negligible 1-butanol when the concentrations of KF and K2CO3 in the water phase were equal to or higher than 27.11% and 31.68% , respectively. Thus water could be separated efficiently from 1-butanol-water by adding KF or K2CO3 into the system. A theoretical calculation of LLE data was calculated by using the Pitzer theory to get water activity in the water phase, and by the models, such as the Wilson, NRTL or the UNIQUAC for the 1-butanol phase. For 1-hutanol-water-KF system, the experimental data were found in good agreement with the calculated results by using Pitzer theory and Wilson equa tion, while for 1-butanol-water-K2CO3 system, the experimental data were found in good agreement with the calculated results by using Pitzer theory and UNIQUAC eauation.     

Liquid-Liquid Equilibrium for 1-Butanol-Water-KF and 1-Butanol-Water-K_2CO_3 Systems

The1butanolformsazeotropewithwa ter[1],andcannotbeextractedtoahighconcentrationfromtheaqueoussolutionbytheordinarydistillationmethod.Inthiscase,azeo tropicdistillationisoftenused.Forazeotropicdistillation,however,boththeazeotropicentrai nerandwatermustbevaporizedintothetopof anazeotropicdistillationcolumninordertoob taintheanhydrous1butanolatthebottom.Inaddition,theamountofazeotropicentraineris usuallylarge,whichleadstohighenergycon sumption.Forthisreason,useofKForK2CO3toseparateisopropanol …     

(1+1)维积分微分 Ito方程的精确行波解

利用平面动力系统理论和方法对Ito方程等价的平面动力系统进行定性分析,得出Ito方程存在2个钟状孤波解和若干个有界行波解.借助辅助方程法给出了Ito方程的2个钟状孤波解和若干有界行波解的精确表达式,并且这些精确解的显式表达式是首次被得到,以往文献中的结果可以作为文中精确解的推论.     

丢番图方程ｙ2＋（ｙ＋１）2＝３ｘ2的正整数解

利用Pell方程、商高方程本原解,证明了丢番图方程ｙ²＋（ｙ＋１）²＝３ｘ²正整数解的通解公式,并对通解公式作了验证.     

(1+1)维修正的Korteweg-deVries方程的对称精确解研究

利用改进的Riccati方程映射方程法,结合变量分离法,通过假设的对称形式解,借助Maple符号计算软件,分析计算(1+1)维修正的Korteweg-de Vries方程的精确解(包括孤波解、周期波解和有理函数解)。     

求解相容的矩阵方程组A_1 XB_1=D1,A_2XB_2=D_2的一种迭代法

给出了求解矩阵方程组A1XB1=D1,A2 XB2 =D2 的迭代法 .